Key-reuse check algorithm re-checks already known keys for each new sector key found

[aczid]

Excerpt of the problem:

Sector 38 - Unknown Key A               Unknown Key B
Sector 39 - Found   Key A: 000000000000 Found   Key B: 000000000000

...

     266 | 22A |    1907 | Brute force phase completed. Key found: 72de9a8d5256    |               0 |    0s          
Checking for key reuse...
[Key: 000000000000] -> [xxxxxxxxxxxxxxxxxxxxxx/................x]
[Key: 72de9a8d5256] -> [xxxxxxxxxxxxxxxxxxxxxx/..........

This is not the smart way to do it, and also it appears the code hangs there. :-(

I would expect the key-reuse check to only test the newly found key, and keep its earlier sector key results.