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Complete Solution for JSparser StrinIO issue and handler.py issue

Open hitesh9811 opened this issue 3 years ago • 2 comments

solution for StringIO issue in safeurl.py

  • open safeurl.py and change import StringIO to import io

Now open handler.py and do following

  • go to line 11 and change from cgi import escape to from html import escape

  • Add this below line 11 import html

  • Go to line 4 in handler.py and change urlparse to urlib.parse

hitesh9811 avatar Jun 13 '21 20:06 hitesh9811

Use urllib.parse and not urlib.parse

This will solve the issue

gokuss9 avatar Jul 13 '21 19:07 gokuss9

I get the following error pycurl.error: (23, 'failure writing output to destination')

AkagamiNoShanks avatar Feb 09 '22 02:02 AkagamiNoShanks