xcodebuild
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How to specify the output dir ?
When I used this action build a iOS project using below code:
- uses: mxcl/xcodebuild@v1
with:
platform: iOS
action: build
configuration: release
working-directory: project/ios
scheme: XXX
I get the below log:
▸ xcodebuild build
.....
▸ Touching XXX.framework (in target 'XXX' from project 'XXX')
▸ Build Succeeded
Now i want to get XXX.framework
and upload, but i can't find a way to set the output dir
Not possible with the current action I believe. This action was designed for CI not CD so that makes sense. Though I agree we should support this.
It should be pretty easy to add it. We are simply a GHA wrapper around running xcodebuild, add the flag in action.yml
and use it in the code.
Thanks! Looking forward to add this arg.
I submit a pr, please review it