Unit error in Modelica.Electrical.Analog.Examples.CauerLowPassAnalog

[qlambert-pro]

Both the value of capacitance c2 and c4 are expressed as inverse of inductance l1 and l2 respectively.

[HansOlsson]

That makes it sound worse than it is - as they are expressed as: parameter SI.Capacitance c2=1/(1.704992^2*l1); so it would make sense if 1.704992 had unit Hz (and similarly for c4).

However, that made me realize that there's a lot of documentation missing for these examples - it's stated that it's a 5th order low-pass filter (obviously a Cauer or elliptic filter), but it doesn't specify the coefficients like frequency, ripple, and selectivity.

[christiankral]

Some possible solutions are:

1. Remove the example as the documentation is not sufficient at all
2. Just replace parameter SI.Capacitance c2=1/(1.704992^2*l1) by parameter SI.Capacitance c2=1/(1.704992^2*1.304) and leave the example as it is, as it is "just" an example
3. Replace the example by a new and well documented example of such a fifth order filter: this sounds like a lot of work (for an example that I personally think is not too exciting at all ...)