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[Feature] Calculate: Find Roots of an Equation
Hey folks! 👋🏼 Do we have any feature to find the roots of an equation (whether it will a quadratic or linear equation) in one tap?
A quadratic equation is a second-order polynomial equation of a variable say x. The general form of a quadratic equation is given as:
a*x2 + b*x + c = 0
Where a,b and c are real known values and,
a can't be zero.
A quadratic equation has two roots. The roots of a quadratic equation can be easily obtained by using the quadratic formula:
roots = (-b ± √(b2 - 4ac))/2a
Derivation:
ax2 + bx + c = 0
or, ax2 + bx = -c
or, x2 + (b/a)x = -(c/a)
or, x2 + (b/a)x + (b2/4a2) - (b2/4a2) = -(c/a)
or, x2 + (b/a)x + (b2/4a2) = -(c/a) + (b2/4a2)
or, (x + b/2a)2 = -(c/a) + (b2/4a2)
or, (x + b/2a)2 = (b2 - 4ac) /4a2
or, (x + b/2a) = ± √(b2 - 4ac) /2a
or, x = (-b ± √(b2 - 4ac))/2a
There arises three cases as described below while finding the roots of a quadratic equation:
If b2 < 4ac, then roots are complex
(not real).
For example, roots of x2 + x + 1 = 0 are
-0.5 + i1.73205 and -0.5 - i1.73205
If b2 = 4ac, then roots are real
and both roots are same.
For example, roots of x2 - 2x + 1 = 0 are 1 and 1
If b2 > 4ac, then roots are real
and different.
For example, roots of x2 - 7x - 12 = 0 are 3 and 4
I didn't have any clue whether, that features is already there or not? If its not, Can I proceed to work on it? Pl help me look out!
This is your friendly Microsoft Issue Bot. I've seen this issue come in and have gone to tell a human about it.
This pitch looks like it has everything it needs for review. In the meantime, we'll keep this idea open for discussion so the community has the chance to provide feedback. Check out our New Feedback Process for more info on the user-centered process we follow for new feature development.
Sir, I've a blue-print code for this, but doesn't know how to implement it with Microsoft modules/features? Can I take this issue & enhance my knowledge, & work on same issue further?
Cubic and quartic equations should also be covered. Closed form solutions exist for them. Linear and quadratic equations can be solved in memory, if the coefficients are "nice". Cubics and quartics - not so easily. And that's a job for Calculator.
Can I know @TrangOul, like, specifically what are you talking about? I get, this issue is reg. calculate roots of equations, and you're basically talking about Cubic & Quartics ie, under functions & ranges..
You may refer this, Sir.
I mean the equations ax^3 + bx^2 + cx + d = 0 and ax^4 + bx^3 + cx^2 + dx + e = 0, with known complex coefficients a, b, c, d, e. Closed form solutions exist: cubic and quartic. They look messy, indeed, but we can extract and re-use partial results, just like we substitute Δ = b^2 - 4ac in quadratic equation.
Yeah, it sounds good ! & may be.. this reduce our work for an instant as function.. right I agree with you.. but this functions are only applicable for Cubic, Quartic & Quintic equations, let me know if we find multiple roots from this method?
Declaration as per theory :
x3 + ax2 + bx + c = 0 : Cubic equation
x4 + ax3 + bx2 + cx + d = 0: Quartic equation
x5 + ax4 + bx3 + cx2 + dx + e = 0 = 0: Quintic equation
Quintics have a form ax^5 + bx^4 + cx^3 + dx^2 + ex + f (notice the fifth power) and they do not have a general solution. The provided code solves them (and quartics) numerically.
Also, you've missed terms with x in 3rd and 4th degree equations.
Yeah, I get your point, basically I'm dealing with quadratic in example, but we can stick with Cubic, Quartic and Quintic equation as well.. Thats great! If these functions, fulfill our needs, we like to recommend for a single button for all kinds of equations.. <3
Can I work on this issue?
If @Swastyy is not working on this issue!
There is not much work done, so @Meenakshi-gthub can start doin it.