Can we have a parameterless None.Of<T>() method ?

[TheOnlyMrFlow]

Hi, I'm wondering why there is only a version of None.Of<T>(T t) that takes a parameter ?

I think it would make sense to have that same method without parameter, like this :

public static OneOf.OneOf<T, None> Of<T>() => (OneOf.OneOf<T, None>) new None();

Here is my use case :

public OneOf<Foo, None> FindFoo()
        => aMethodThatReturnsFooOrNull() ?? None.Of<Foo>();

Currently this is how I have to handle this :

public OneOf<Foo, None> FindFoo()
        => aMethodThatReturnsFooOrNull() ?? None.Of<Foo>(null!);

Btw thx for the lib, it is great.

[emperador-ming]

Same here.

We use:

public OneOf<Foo, None> FindFoo()
        => aMethodThatReturnsFooOrNull() ?? None.Of<Foo>(default!);

This would be great:

public OneOf<Foo, None> FindFoo()
        => aMethodThatReturnsFooOrNull() ?? None.Of<Foo>();

[emperador-ming]

Workaround

using OneOf;
using OneOf.Types;

namespace SuD.Domain.Extensions;

public static class NoneExtensions
{
    public static OneOf<T, None> Of<T>(this None _) => (OneOf<T, None>)default(None);
}

public OneOf<Foo, None> FindFoo()
        => aMethodThatReturnsFooOrNull() ?? new None().Of<Foo>();

[mcintyre321]

I have been thinking about a static OneOf.Types.Factory class with a None method, then you can do a using static OneOf.Types.Factory and just return None()

On Tue, 10 May 2022, 19:06 emperador-ming, @.***> wrote:

Workaround

using OneOf;

using OneOf.Types;

namespace SuD.Domain.Extensions;

public static class NoneExtensions { public static OneOf<T, None> Of<T>(this None _)

{
    return (OneOf<T, None>)default(None);
}

}

public OneOf<Foo, None> FindFoo() => aMethodThatReturnsFooOrNull() ?? new None().Of<Foo>();

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