kue-scheduler job:undefined when prefix contain colon symbol

job:undefined when prefix contain colon symbol

Open vothanhkiet opened this issue 7 years ago • 5 comments

When validate expired key, we've already include the prefix, however, when extract the job unique ID, we assume that the expired key has only 3 or 4 parts, therefore, if the prefix contain additional colon symbol, _getJobUUID return undefined value

queue._jobExpiryKeyValidator = new RegExp('^' + queue.options.prefix + ':scheduler:(?!' + lockKey + ')');

  var uuid;

  var splits = key.split(':');

  //deduce job uuid from job expiry key
  //kue:scheduler:<jobExpirykey>
  if (splits.length === 3) {
    uuid = splits[2];
  }

  //deduce job uuid from job data key
  //kue:scheduler:data:<jobExpirykey>
  if (splits.length === 4) {
    uuid = splits[3];
  }

Solution: can we use the last part as UUID ?

  var splits = key.split(':');

  splits = _.filter(splits, function(o) { return o !== ''; });
  if(splits.length > 0){
    uuid = splits[splits.length - 1];
  }