Louis Wasserman
Louis Wasserman
That might actually be easier to prove by working directly with classical-Fin and constructing a new equivalence, rather than the preexisting product-Fin...
I'm uncertain. I am mostly planning to go from Bishop's proof in Foundations of Constructive Analysis, and I don't see any choice principles in that proof yet; he accepts countable...
I see now that it uses dependent choice, actually.
Was already working on it. Sent!
#1341 seems to be hitting this too.
I'm excited to see this work; I attempted once or twice to tackle the commutative semiring of cardinalities but didn't get very far.
Is this theorem on the 100 Theorems list? If not, I feel less urgency about the classical formulation.