uv_timer_init and uv_timer_stop

[qiupin]

• Version: 1.34.2-1ubuntu1
• Platform: 4.19.84-microsoft-standard when uv_timer_init is called, a handle will be insert into loop->handle_queue, but how can I remove it from the loop->handle_queue after the timer is stop?

I wrote some testing code, and I got a dead loop.

#include <uv.h>
#include <iostream>
#include "queue.h"

using namespace std;

int main(int argc, char const* argv[])
{
    uv_loop_t* loop = uv_default_loop();
    uv_timer_t t;

    uv_timer_init(loop, &t);

    uv_timer_start(&t, nullptr, 1000, 1000);
    uv_timer_stop(&t);
    uv_close((uv_handle_t*)&t, nullptr);

    cout << "init again" << endl;
    uv_timer_init(loop, &t);
    uv_print_all_handles(loop, stdout);

    uv_timer_start(&t, nullptr, 1000, 1000);
    //uv_print_all_handles(loop, stdout);
    uv_timer_stop(&t);
    //uv_print_all_handles(loop, stdout);
    uv_close((uv_handle_t*)&t, nullptr);
    //uv_print_all_handles(loop, stdout);

    return 0;
}

[bnoordhuis]

uv_close() will remove the timer again.

However, you're reinitializing it again immediately after calling uv_close(). Don't do that, you need to call uv_run() first and wait for the close callback.

[qiupin]

I get it. Thank you very much.

发自我的iPhone

在 2020年7月21日，下午4:55，Ben Noordhuis [email protected] 写道：

 uv_close() will remove the timer again.

However, you're reinitializing it again immediately after calling uv_close(). Don't do that, you need to call uv_run() first and wait for the close callback.

— You are receiving this because you authored the thread. Reply to this email directly, view it on GitHub, or unsubscribe.