go-libp2p
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libp2p
Libp2p fails to determine default route on FreeBSD
On FreeBSD, netroute.Router.Route('0.0.0.0') returns an error instead of returning the default route. We need some other way to determine the default route. We could just try looking up a well known IP address.
https://github.com/libp2p/go-libp2p/blob/6a3b138a57ed3ad31d531906f47b3f3cc1d8d9b6/p2p/host/basic/basic_host.go#L260-L280
what error do you get? I'm guessing you're able to load the routing table, but asking for the route is failing?
just to confirm, you're specifically referring to FreeBSD, and not macs, right?
spun up a FreeBSD VM and can't reproduce:
FreeBSD 12.1-RELEASE r354233 GENERIC amd64
The RIB's returned by the system call are:
rtNFO: &{10.0.2.15/0 0.0.0.0/0 10.0.2.2 10.0.2.15 0 1 0}
rtNFO: &{10.0.2.15/32 10.0.2.0/24 <nil> 10.0.2.15 0 1 0}
rtNFO: &{127.0.0.1/32 10.0.2.15/32 <nil> 127.0.0.1 0 2 0}
rtNFO: &{127.0.0.1/32 127.0.0.1/32 <nil> 127.0.0.1 0 2 0}
rtNFO: &{::1/128 ::1/128 <nil> ::1 0 2 0}
rtNFO: &{fe80::1/128 fe80::/64 <nil> fe80::1 0 2 0}
rtNFO: &{fe80::1/128 fe80::1/128 <nil> fe80::1 0 2 0}
(em0 network interface 10.0.2.15/24 with gw 10.0.2.2)
default route works as expected in this case.
I think to debug / reproduce, the most useful thing to do would be to modify here to insert the line fmt.Printf("rtNFO: %v", routeInfo)
so that we can try to understand what's happening with regards to the parsed routing table.
Cannot reproduce
FreeBSD 14.1-RELEASE releng/14.1-n267679-10e31f0946d8 GENERIC amd64
Printing route info here shows results similary to above. Default route is found.
Maybe this issue was reported on a host that only has IPv6 addresses and no default route was found for 0.0.0.0?
In either case, this does not seem to be a defect (or has not been for a long time), so suggest closing this issue.
It had an IPv4 address. But this was a long time ago on a machine that no longer exists (and was probably in a FreeBSD jail). Given that nobody can reproduce, I'm just going to close this.