FE-Interview
FE-Interview copied to clipboard
实现以下代码
function add() {
// your code
}
function one() {
// your code
}
function two() {
// your code
}
console.log(add(one(two()))); //3
console.log(add(two(one()))); //3
扫描下方二维码,获取答案以及详细解析,同时可解锁800+道前端面试题。
有解题思路吗?函数式编程?
有解题思路吗?函数式编程?
function add() {
// your code
return arguments[0].reduce((a,b)=>a+b)
}
function one() {
// your code
if(arguments.length==0){
return 1
}else{
return [arguments[0],1]
}
}
function two() {
if(arguments.length==0){
return 2
}else{
return [arguments[0],2]
}
}
console.log(add(one(two()))); //3
console.log(add(two(one()))); //3
function add(res) {
// your code
return res
}
function one(res) {
// your code
const value = 1
if (res) {
return res + value
}
return value
}
function two(res) {
// your code
const value = 2
if (res) {
return res + value
}
return value
}
console.log(add(one(two()))) //3
console.log(add(two(one()))) //3