无环链表相交 解法太复杂

[zqiang3]

[zqiang3]

class Solution(object):
    def getIntersectionNode(self, headA, headB):   
                
        cura, curb = headA, headB
        
        while cura is not curb:
            cura = cura.next if cura else headB
            curb = curb.next if curb else headA
                                
        return cura