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获取token,参数值错误,直接抛异常,而且异常信息不是json,如何解析code值,代码如下

Open xyZangGit opened this issue 2 years ago • 0 comments

Map<String, Object> appAccessTokenBody = new HashMap<>(); appAccessTokenBody.put("app_id", Constant.FeiSuOpenAiAppId); appAccessTokenBody.put("app_secret", Constant.FeiSuOpenAiAppSecret);

    try {
        RawResponse resp = getClient().post(Constant.FeiShuAppAccessToken, appAccessTokenBody, AccessTokenType.Tenant);

        // 处理结果
        System.out.println(resp.getStatusCode());
        System.out.println(Jsons.DEFAULT.toJson(resp.getHeaders()));
        System.out.println(new String(resp.getBody()));
        System.out.println(resp.getRequestID());
    } catch (Exception e) {
        e.printStackTrace();
    }

xyZangGit avatar Mar 30 '23 01:03 xyZangGit