Rss feed with errors with feedparser but ok in w3c

[frague59]

trafficstars

Hi,

I'm trying to parse a RSS 2.0 feed :

http://www.legrandmix.com/data/rss.xml

It is OK with w3c validator : https://validator.w3.org/feed/check.cgi?url=http%3A%2F%2Fwww.legrandmix.com%2Fdata%2Frss.xml

But I've an error with feedparser :

SAXParseException('not well-formed (invalid token)'

I'm using the last version of feedparser (5.2.1) on python 2.7.10+, on Debian Linux.

Thanks for your help !

[kurtmckee]

Testing this in develop branch on python 2.7.11 on Ubuntu and I'm not able to reproduce the problem.

Please confirm that the issue continues if you manually download the feed file (and confirm its contents!) and parse that with code from the current develop branch.

[evdoks]

Had a similar problem. In my case I forgot to put http:// in front of URL.

[buhtz]

The link itself is invalid now. So we can not test to reproduce this anymore. Can be closed.