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Correct the answer of Probability Question 10.

Open ashutoshaay26 opened this issue 4 years ago • 0 comments

The second answer(Expected number of Hash Collisions) should be 10 - 10*(1−(1−1/10)^10) The third answer(Expected number of Hashes unused) should be 10*(1−(1−1/10)^10)

ashutoshaay26 avatar Oct 10 '20 09:10 ashutoshaay26