The "mod" math remainder operator shall always return an integer

[lvcabral]

Even if both numbers are float or double the result is an integer in Roku.

[strattonbrazil]

Can you provide some test cases for this? I tried the following:

?type(3 mod 2&)
?type(7.5 mod 3)
?type(9& mod 2)

and get:

LongInteger
Float
LongInteger

[lvcabral]

The issue is not the type returned but the actual value:

'In Roku
? 7.5 mod 3
 1
 'In BRS
? 7.5 mod 3
 1.5