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Resource.asPath()

Open javaConductor opened this issue 9 years ago • 0 comments

Should return the same resource with the specified pathPrefix. Each Actioin inside should now be rooted at the New Path.

def r = resource('/one'){ ... }

http{

resource r.asPath("/two") }

Maybe "withPath(str)" is better??!&$%%

javaConductor avatar May 27 '15 21:05 javaConductor