James Johnson

Please merge. Version v1.4.4 has a [bugfix](https://groups.google.com/forum/#!searchin/jquery-ui-layout/lang/jquery-ui-layout/nJXoIW4IjxM/npSl0VURjJ4J) I need. Thanks!

@justin-schroeder Thanks for the explanation. Yes, setting the value to undefined or any string (empty or not) it works without error. I wasn't expecting to get an error when setting...

I too ran into this issue.

I suggest trying it without the `->where('product_id','=',$this->id);` in your query. ...edit Sorry, I didn't pay attention enough attention to your issue description :(. Have you looked at the request going...

@CoolCookie with this pull request you can do ```php ->column('status', label: 'Status', classes: function ($value, $item) { if ($value === 'Approved') { return 'text-green'; } if ($value === 'Cancelled') {...

Is there a way to do that without changing the gulp build script every time there is a change to the list of stylesheets or scripts? I really don't want...

What I'm looking for is a way to specify the output in the html file. A static output file won't work when I different dependencies on for a bunch html...