phpsa

phpsa copied to clipboard

$a = 1;
unset($a);

var_dump($a); // Undefined?

i think unset() is a function and no operator. Maybe we should also add a warning to the (unset) cast since it is not the same as the unset() function. (and the (unset) cast is pretty useless)

@ddmler Hey!

Unset can be

• Operator

unset $a;

• Function http://php.net/manual/ru/function.unset.php

unset($a):

I created another issue for unset fcall https://github.com/ovr/phpsa/issues/70

So, I am wrong unset is an operator (because it's handled by VM OPCODE) but with function call like syntax

And @nikic's php-parser named it like PhpParser\Node\Stmt\Unset_

From PHP-src I didnt find PHP_FUNCTION(unset) but find statement with opcode Review https://github.com/php/php-src/blob/2ae21abdf7b87ee95d76aca22e787408d7c766cf/Zend/zend_vm_opcodes.c#L99

Seems there are some parts

• [ ] Unset variable from Context->SymbolTable
• [ ] Unset referenced variables
• [ ] Unset for object property
• [ ] Magic __unset method
• [ ] Unset for array type