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Published 20 hours ago • verified publisher icon harvardnlp

nonedenom is not working as claimed

Open wwt17 opened this issue 2 years ago • 0 comments

Here you're getting num_to_keep based on the number of examples not labeled as NONE (len(trlabels)-len(none_idxs)); however, according to the comment above you should use the number of examples labeled as NONE (len(none_idxs)).

wwt17 avatar Aug 25 '22 01:08 wwt17