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Update removeStopWords method

Open abhinavp13 opened this issue 7 years ago • 1 comments

It was checking for is Stopword(string), which is the method input string. After splitting on spaces, we have word in words, so isStopword should be called with word as string parameter.

abhinavp13 avatar Mar 22 '17 11:03 abhinavp13

The program is not running properly. Can anyone tell me which method to call in the main.

harshi58 avatar Jan 20 '18 04:01 harshi58