GmSSL 3.1.0版本SM2加密之后在OpenSSL 1.1.1t版本上解密不了#哪位大佬有遇到这问题麻烦回答一下#

SM2加密之后无法在OpenSSL 1.1.1t版本上解密不了#哪位大佬有遇到这问题麻烦回答一下#折腾了几天了又不熟悉···。

Sep 28 '23 02:09 xiexuetao

gmssl命令行生成的加密串为 asn1(c1x, c1y, c2,c3) , 大概率是用openssl生成的字符串的格式不对，需要进行整合，PS：我在网上找一圈都没找到openssl命令的ecc 非对称加密的命令，具体命令是什么，你用命令加密一个串出来，我看看是什么格式的

Sep 28 '23 07:09 lpilp

gmssl命令行生成的加密串为 asn1(c1x, c1y, c2,c3) , 大概率是用openssl生成的字符串的格式不对，需要进行整合，PS：我在网上找一圈都没找到openssl命令的ecc 非对称加密的命令，具体命令是什么，你用命令加密一个串出来，我看看是什么格式的实现方法：

(nullable NSData *)enData:(NSData *)plainData hexPubKey:(NSString *)hexPubKey{ uint8_t *plain_bytes = (uint8_t *)plainData.bytes; // 明文 const char *public_key = hexPubKey.UTF8String; // 公钥 size_t msg_len = plainData.length; // 明文长度

const EVP_MD *digest = EVP_sm3(); // 摘要算法 EC_GROUP *group = EC_GROUP_new_by_curve_name(kDefaultEllipticCurveType); // 椭圆曲线 EC_KEY *key = NULL; // 密钥对 EC_POINT *pub_point = NULL; // 坐标 uint8_t *ctext = NULL; // 密文 NSData *cipherData = nil; // 密文 do { key = EC_KEY_new(); if (!EC_KEY_set_group(key, group)) { break; }
```
  pub_point = EC_POINT_new(group);
  EC_POINT_hex2point(group, public_key, pub_point, NULL);
  if (!EC_KEY_set_public_key(key, pub_point)) {
      break;
  }

  size_t ctext_len = 0;
  if (!sm2_ciphertext_size(key, digest, msg_len, &ctext_len)) {
      break;
  }

  ctext = (uint8_t *)OPENSSL_zalloc(ctext_len);
  if (!sm2_encrypt(key, digest, plain_bytes, msg_len, ctext, &ctext_len)) {
      break;
  }

  cipherData = [NSData dataWithBytes:ctext length:ctext_len];
```
} while (NO);

if (group != NULL) EC_GROUP_free(group); EC_POINT_free(pub_point); OPENSSL_free(ctext); EC_KEY_free(key);

return cipherData; } 加密结果： 306E02201C20E109582352A8500BFFF7F23B72A2CC4D7DDD989BAC24D946B7EB501D531002205F9A26785A19D33CF1CAADD5D4987014C7A07CA4A2DF60B2D02B676D72EAD01A04209738C376FFADCDA2B8303FDB5ABF5E53A655C0A97835E93007501FD9BD33C8DC04064B01535F00E6

Oct 07 '23 02:10 xiexuetao

int sm2_encrypt(const EC_KEY *key, const EVP_MD *digest, const uint8_t *msg, size_t msg_len, uint8_t *ciphertext_buf, size_t *ciphertext_len) { int rc = 0, ciphertext_leni; size_t i; BN_CTX *ctx = NULL; BIGNUM *k = NULL; BIGNUM *x1 = NULL; BIGNUM *y1 = NULL; BIGNUM *x2 = NULL; BIGNUM *y2 = NULL; EVP_MD_CTX *hash = EVP_MD_CTX_new(); struct SM2_Ciphertext_st ctext_struct; const EC_GROUP *group = EC_KEY_get0_group(key); const BIGNUM *order = EC_GROUP_get0_order(group); const EC_POINT *P = EC_KEY_get0_public_key(key); EC_POINT *kG = NULL; EC_POINT *kP = NULL; uint8_t *msg_mask = NULL; uint8_t *x2y2 = NULL; uint8_t *C3 = NULL; size_t field_size; const int C3_size = EVP_MD_size(digest);

/* NULL these before any "goto done" */
ctext_struct.C2 = NULL;
ctext_struct.C3 = NULL;

if (hash == NULL || C3_size <= 0) {
    SM2err(SM2_F_SM2_ENCRYPT, ERR_R_INTERNAL_ERROR);
    goto done;
}

field_size = ec_field_size(group);
if (field_size == 0) {
    SM2err(SM2_F_SM2_ENCRYPT, ERR_R_INTERNAL_ERROR);
    goto done;
}

kG = EC_POINT_new(group);
kP = EC_POINT_new(group);
ctx = BN_CTX_new();
if (kG == NULL || kP == NULL || ctx == NULL) {
    SM2err(SM2_F_SM2_ENCRYPT, ERR_R_MALLOC_FAILURE);
    goto done;
}

BN_CTX_start(ctx);
k = BN_CTX_get(ctx);
x1 = BN_CTX_get(ctx);
x2 = BN_CTX_get(ctx);
y1 = BN_CTX_get(ctx);
y2 = BN_CTX_get(ctx);

if (y2 == NULL) {
    SM2err(SM2_F_SM2_ENCRYPT, ERR_R_BN_LIB);
    goto done;
}

x2y2 = OPENSSL_zalloc(2 * field_size);
C3 = OPENSSL_zalloc(C3_size);

if (x2y2 == NULL || C3 == NULL) {
    SM2err(SM2_F_SM2_ENCRYPT, ERR_R_MALLOC_FAILURE);
    goto done;
}

memset(ciphertext_buf, 0, *ciphertext_len);

if (!BN_priv_rand_range(k, order)) {
    SM2err(SM2_F_SM2_ENCRYPT, ERR_R_INTERNAL_ERROR);
    goto done;
}

if (!EC_POINT_mul(group, kG, k, NULL, NULL, ctx)
        || !EC_POINT_get_affine_coordinates(group, kG, x1, y1, ctx)
        || !EC_POINT_mul(group, kP, NULL, P, k, ctx)
        || !EC_POINT_get_affine_coordinates(group, kP, x2, y2, ctx)) {
    SM2err(SM2_F_SM2_ENCRYPT, ERR_R_EC_LIB);
    goto done;
}

if (BN_bn2binpad(x2, x2y2, field_size) < 0
        || BN_bn2binpad(y2, x2y2 + field_size, field_size) < 0) {
    SM2err(SM2_F_SM2_ENCRYPT, ERR_R_INTERNAL_ERROR);
    goto done;
}

msg_mask = OPENSSL_zalloc(msg_len);
if (msg_mask == NULL) {
   SM2err(SM2_F_SM2_ENCRYPT, ERR_R_MALLOC_FAILURE);
   goto done;

}

/* X9.63 with no salt happens to match the KDF used in SM2 */
if (!ecdh_KDF_X9_63(msg_mask, msg_len, x2y2, 2 * field_size, NULL, 0,
                    digest)) {
    SM2err(SM2_F_SM2_ENCRYPT, ERR_R_EVP_LIB);
    goto done;
}

for (i = 0; i != msg_len; ++i)
    msg_mask[i] ^= msg[i];

if (EVP_DigestInit(hash, digest) == 0
        || EVP_DigestUpdate(hash, x2y2, field_size) == 0
        || EVP_DigestUpdate(hash, msg, msg_len) == 0
        || EVP_DigestUpdate(hash, x2y2 + field_size, field_size) == 0
        || EVP_DigestFinal(hash, C3, NULL) == 0) {
    SM2err(SM2_F_SM2_ENCRYPT, ERR_R_EVP_LIB);
    goto done;
}

ctext_struct.C1x = x1;
ctext_struct.C1y = y1;
ctext_struct.C3 = ASN1_OCTET_STRING_new();
ctext_struct.C2 = ASN1_OCTET_STRING_new();

if (ctext_struct.C3 == NULL || ctext_struct.C2 == NULL) {
   SM2err(SM2_F_SM2_ENCRYPT, ERR_R_MALLOC_FAILURE);
   goto done;
}
if (!ASN1_OCTET_STRING_set(ctext_struct.C3, C3, C3_size)
        || !ASN1_OCTET_STRING_set(ctext_struct.C2, msg_mask, msg_len)) {
    SM2err(SM2_F_SM2_ENCRYPT, ERR_R_INTERNAL_ERROR);
    goto done;
}

ciphertext_leni = i2d_SM2_Ciphertext(&ctext_struct, &ciphertext_buf);
/* Ensure cast to size_t is safe */
if (ciphertext_leni < 0) {
    SM2err(SM2_F_SM2_ENCRYPT, ERR_R_INTERNAL_ERROR);
    goto done;
}
*ciphertext_len = (size_t)ciphertext_leni;

rc = 1;

done: ASN1_OCTET_STRING_free(ctext_struct.C2); ASN1_OCTET_STRING_free(ctext_struct.C3); OPENSSL_free(msg_mask); OPENSSL_free(x2y2); OPENSSL_free(C3); EVP_MD_CTX_free(hash); BN_CTX_free(ctx); EC_POINT_free(kG); EC_POINT_free(kP); return rc; }

Oct 07 '23 02:10 xiexuetao

加密结果：
306E02201C20E109582352A8500BFFF7F23B72A2CC4D7DDD989BAC24D946B7EB501D531002205F9A26785A19D33CF1CAADD5D4987014C7A07CA4A2DF60B2D02B676D72EAD01A04209738C376FFADCDA2B8303FDB5ABF5E53A655C0A97835E93007501FD9BD33C8DC04064B01535F00E6

格式上没有问题，这个格式与 gmssl 加密出来看格式一样的，那就是别的问题，只能你一步步调试了，

Oct 07 '23 03:10 lpilp

你这段是加密的，你这段加密的代码，用你自己的解密的可以解出来不

Oct 07 '23 05:10 lpilp

你这段是加密的，你这段加密的代码，用你自己的解密的可以解出来不

可以解的

Oct 07 '23 06:10 xiexuetao

你这段是加密的，你这段加密的代码，用你自己的解密的可以解出来不

加密结果：
306E02201C20E109582352A8500BFFF7F23B72A2CC4D7DDD989BAC24D946B7EB501D531002205F9A26785A19D33CF1CAADD5D4987014C7A07CA4A2DF60B2D02B676D72EAD01A04209738C376FFADCDA2B8303FDB5ABF5E53A655C0A97835E93007501FD9BD33C8DC04064B01535F00E6
格式上没有问题，这个格式与 gmssl 加密出来看格式一样的，那就是别的问题，只能你一步步调试了，好的，我再调试看看。感谢！！

Oct 07 '23 06:10 xiexuetao

@lpilp 我调试gmssl解密OpenSSL密文的时候在下面的这个方法出错了，**in != tag为true导致解密失败这个tag对应的宏是 ASN1_TAG_SEQUENCE = 0x30, int asn1_type_from_der(int tag, const uint8_t **d, size_t *dlen, const uint8_t **in, size_t *inlen) { if (!d || !dlen || !in || !(*in) || !inlen) { error_print(); return -1; }

// tag
if (*inlen == 0 || **in != tag) {
	*d = NULL;
	*dlen = 0;
	return 0;
}
(*in)++;
(*inlen)--;

// length
if (asn1_length_from_der(dlen, in, inlen) != 1) {
	error_print();
	return -1;
}

// data
*d = *in;
*in += *dlen;
*inlen -= *dlen;
return 1;

}

Oct 07 '23 08:10 xiexuetao

你的加密串格式是没有问题的，第一个字符就是0x30

gmssl sm2decrypt -key sm2.pem -pass 1234 -in sm2.der

这里的 sm2.der里要求存的原始字符bin类型，打开看是乱码，你试的时候是不是把 hex 的 ‘306E02201C20E1095823....’ 存进去了

Oct 07 '23 08:10 lpilp

你的加密串格式是没有问题的，第一个字符就是0x30
gmssl sm2decrypt -key sm2.pem -pass 1234 -in sm2.der
这里的 sm2.der里要求存的原始字符bin类型，打开看是乱码，你试的时候是不是把 hex 的 ‘306E02201C20E1095823....’ 存进去了

是的，用了hex····

Oct 08 '23 01:10 xiexuetao

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3.1.0版本SM2加密之后在OpenSSL 1.1.1t版本上解密不了#哪位大佬有遇到这问题麻烦回答一下#

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