manipulating e^(i * pi) ?

[LewisHoff]

I get a (false,i^i) when trying to solve e^(i * pi) + 1 = 0 using OldSolve to get steps to a solution I know exists of i^i = e^(pi/2) either side evaluates to 2.07 . i is the sqrt of -1 e is exponential base pi is π. ? Is there a tutorial for complex powers of complex numbers ? Thank You. Lewis

[grzegorzmazur]

Hi,

In> Exp(I*Pi) + 1
Out> 0

and

In> I^I
Out> Exp(-Pi/2)

although the latter result is let's say controversial (it's ok to calculate powers of the complex numbers when the power is an integer, otherwise things get messy).

Sorry it took so long, Grzesiek