ic| Error: Failed to access the underlying source code for analysis.

[mhechthz]

This was already in the issues but nevertheless I face this currently.

from icecream import ic

a = 3
b = 4
ic(a+b)

ic| Error: Failed to access the underlying source code for analysis. Was ic() invoked in a REPL (e.g. from the command line), a frozen application (e.g. packaged with PyInstaller), or did the underlying source code change during execution?

Windows 10, Python 3.11.6. On the same machine Python 3.10 and Python 3.12 work fine, but 3.11 not.

python -VV
Python 3.11.6 (tags/v3.11.6:8b6ee5b, Oct  2 2023, 14:57:12) [MSC v.1935 64 bit (AMD64)]

[char101]

Works for me with python 3.11.6 on Windows. You could test if executing works first e.g.

import inspect

import executing


def test(expr):
    source = executing.Source.executing(inspect.currentframe().f_back)
    print(source.text()) # should print `test(a + b)`


a = 3
b = 4
test(a + b)

If it doesn't work then the problem is in executing, then you could debug the Source class in executing.

[mhechthz]

I think it might be an incompatibility with some library or so.

In Python 3.10 and 3.12 the print is as expected, in my 3.11.6 the print is empty.

[TheStrangerDoctor]

Please close this issue if it is solved to prevent comment cluttering. TQ

[RainerFaller]

I had the same problem with a fresh venv and Python 3.11.7. I resolved it by replacing the complete /site-packages/executing folder by the most recent source distribution 2.0.1