SolutionQCQINielsenChuang
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9.14 Correction
In the box,
This is wrong. A positive operator makes sure that it has non-negative eigenvalues.
When performing $\sqrt A$, you need to sqrt the eigenvalues under the expression of spectral decomposition:
$$ \sqrt A = \sum_i \sqrt \lambda_i | i \rangle \langle i | $$