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Published 20 hours ago • verified publisher icon google

Add UUID.fromString() check to AlwaysThrows

Open sixcorners opened this issue 3 years ago • 1 comments

Fixes #3006

sixcorners avatar Feb 24 '22 16:02 sixcorners

I'm confused...

UUID.fromString(...) only throws "...If name does not conform to the string representation as described in toString()"

kluever avatar Apr 30 '22 00:04 kluever