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Published 20 hours ago • verified publisher icon fool2fish

Update 4.6.md fix wrong answers.

Open ax7e opened this issue 2 years ago • 0 comments

Since $B\to aBAB, B\to \epsilon$, then $FOLLOW(A) = FOLLOW(A) \cup FOLLOW(B)$, so $FOLLOW(A) = {+,*,a,$}$.

ax7e avatar Mar 30 '22 06:03 ax7e