flamingo-svg-transcoder Incomplete transformation

when I transform the following svg, the path p2 does not show up in the java icon.

<?xml version="1.0" encoding="UTF-8" standalone="no"?>
<!DOCTYPE svg PUBLIC "-//W3C//DTD SVG 1.1//EN" "http://www.w3.org/Graphics/SVG/1.1/DTD/svg11.dtd">
<svg xmlns:svg="http://www.w3.org/2000/svg" xmlns="http://www.w3.org/2000/svg" xmlns:xlink="http://www.w3.org/1999/xlink" width="300" height="300" id="svg2" version="1.1">
  <defs id="defs4">
    <linearGradient id="lg1">
      <stop id="s1" offset="0" style="stop-color:white;stop-opacity:0;"/>
      <stop id="s2" offset="1" style="stop-color:white"/>
    </linearGradient>
    <linearGradient xlink:href="#lg1" id="lg3" x1="191" y1="156" x2="148" y2="10" gradientUnits="userSpaceOnUse"/>
    <linearGradient id="lg2">
      <stop style="stop-color:#D5FFD5;stop-opacity:1;" offset="0" id="s3"/>
      <stop style="stop-color:#80FF80;stop-opacity:1;" offset="0.36" id="s4"/>
      <stop style="stop-color:#2AFF2A;stop-opacity:1;" offset="0.79" id="s5"/>
      <stop style="stop-color:#00FF00;stop-opacity:1;" offset="1" id="s6"/>
    </linearGradient>
    <radialGradient xlink:href="#lg2" id="rg1" cx="-100" cy="-278" fx="-100" fy="-278" r="155" gradientUnits="userSpaceOnUse" gradientTransform="matrix(1.267,0,0,1.73,26.67,204.12)"/>
  </defs>
  <g id="layer1" transform="translate(255,539)">
    <path style="stroke:#00D400;fill:url(#rg1);stroke-width:4" id="p1" d="M 54 -394 A 154 154 0 1 1 -254,-394 A 154 154 0 1 1 54 -394 z" transform="matrix(0.949753,0,0,0.949753,-10.31027,-14.52566)"/>
    <path style="fill:url(#lg3)" d="M 150,10 C 74,10 12,71 10,147 C 49,182 87,183 106,174 C 126,165 142,136 168,129 C 194,123 208,124 249,141 C 272,150 269,119 286,116 C 271,55 216,10 150,10 z " transform="translate(-255,-539)" id="p2"/>
  </g>
</svg>

Mar 25 '15 07:03 culmat

Thank you for the report Matthias, I'll look into it. The shape for the path p2 is properly transcoded to Java, but I suspect the gradient definition is not. You can try to tinker the colors on the line with g.setPaint(new LinearGradientPaint(...)) and see if it works better.

Mar 25 '15 07:03 ebourg

Hi Emmanuel, this was my first guess and I tried with Color.black. It does not work. The key is the tranform translate(255,539). If I comment out line 118 of the generated code the icon is rendered corrently.

Mar 25 '15 18:03 culmat