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syntax error caused by unconditional `__has_feature` usage

Open firewave opened this issue 5 months ago • 0 comments

Encountered while working on #438.

# if __has_feature(attribute_availability_with_strict)
# endif
a.cpp:1: syntax error: failed to evaluate #if condition, undefined function-like macro invocation: __has_feature( ... )

See https://gcc.gnu.org/onlinedocs/cpp/_005f_005fhas_005ffeature.html

firewave avatar Aug 04 '25 11:08 firewave