linear-algebra-done-right-solutions
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Solution to 3D.18 wrongly assumes that V is finite-dimensional
In referenced 3.61 vector spaces are set to be finite dimensional.
We can't make use assumption for V from 3D.18
I agree. Do you have a solution?
I know how to solve it if we can take a basis of V, but how to do it if Axler avoids basis of infinite-dimensional stuff?
Define $\phi_v$: $F$ -> $V$ as $\phi_v(f) = fv$, for $v \in V$ and $f \in F$.
$\phi_v \in L(F, V)$, so we can define $\Phi$: $V$ -> $L(F, V)$ as $ \Phi(v) = \phi_v $
Then we can examine the mapping to show that $\Phi$ is invertible.