Create a S3Resource for upload in a more concise way

[tw-kang-namas]

Type: Feature

Is your feature request related to a problem? Please describe. I'm trying to create an excel file and upload it to S3. I'm using fastexcel and it requires an OutputStream to create a Workbook which is the representation of an excel file. What I'm doing looks like..

S3Resource s3Resource = new S3Resource(bucket, key, s3Client, s3OutputStreamProvider);
try (Workbook workbook = new Workbook(s3Resource.getOutputStream(), "name", "version")) {
  ..
}

For this to happen I have to autowire S3Client and S3OutputStreamProvider and pass them to the constructor as above, which I find a little verbose when I'm happy with using the default ones. I checked S3Template.upload() but it requires an InputStream and I couldn't find a way to utilize it in this case.

Describe the solution you'd like Since S3Template already has S3Client and S3OutputStreamProvider, something like S3Resource s3Resource = s3Template.createResource(bucket, key) would be very convenient and easy to read.