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ANTLR (ANother Tool for Language Recognition) is a powerful parser generator for reading, processing, executing, or translating structured text or binary files.

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There is `functionQualifiers : 'const'? 'async'? 'unsafe'? ('extern' abi?)? ;` in the rust grammar from grammars-v4. This seems to give an empty stop on the FunctionQualifiersContext. Is this intentional?

I'm honestly not sure what needs to change in the `package.json` because I thought `"type": "module"`, `"main"` and `"types"` would be enough, but apparently not. The ESM situation is a...

type:question
target:typescript

I'm following the ANTLR4 Reference and have set up antlr with `brew install antlr` and a classpath of: ``` export CLASSPATH=".:/opt/homebrew/Cellar/antlr/4.13.1/antlr-4.13.1-complete.jar" ``` When running TestRig with the `grun -gui` option:...

We are using ANTLR to write a full interpreter. The language is a VBA dialect (oh my!), which includes some ambiguities. As such, ANTLR definitely has some work to do...

So that instead of `class ReportGrammarLexer` it will generate `class EXPORT_TOKEN ReportGrammarLexer` ? It's possible to do it with sed, but I remember grpc generator having an option like that...

Lexer._modeStack Lexer.mode() Token.source Recognizer.getSymbolicNames() Recognizer.getErrorListenerDispatch() [TypeScript missing critical class definition exports](https://github.com/antlr/antlr4/issues/4110#issuecomment-1925751601)

I am building the Swift runtime by running `python boot.py --gen-xcodeproj` in `antlr4/runtime/Swift` (following the instructions in https://github.com/antlr/antlr4/blob/master/doc/swift-target.md) I got this error: ``` warning: 'antlr4': Invalid Exclude '/Users/zhiruzhu/Desktop/Apple-Escrow/antlr4/runtime/Swift/Tests/Antlr4Tests/runtime/Swift/Tests/VisitorCalc.g4': File not...

Hi there, it is planned to release ANTLR4 as a named module for Java? Currently the ANTLR runtime does not have a "module-info.class". This causes problems when using it with...

when i use the antlr to parse postgresql like 'select * from table where id in (1,2,3,4,5,6……15000) ' it occurs the StackOverflowError like this,but the same sql in mysql is...