Simple grammar error

[jtejido]

Hi,

Just wanted to test something simple at first. I'd like to test a program that only start with the word 'fsm' and it out an error saying "<missing 'fsm'>"

the grammar to be tested:

grammar Fsm;

fsm
    :   'fsm' ID
    ;

ID
    :   Letter
    ;

fragment
Letter
    :  '\u0024'           /* $   */ |
       '\u0041'..'\u005a' /* A-Z */ |
       '\u005f'           /* _   */ |
       '\u0061'..'\u007a' /* a-z */ |
       '\u00c0'..'\u00d6' |
       '\u00d8'..'\u00f6' |
       '\u00f8'..'\u00ff' |
       '\u0100'..'\u1fff' |
       '\u3040'..'\u318f' |
       '\u3300'..'\u337f' |
       '\u3400'..'\u3d2d' |
       '\u4e00'..'\u9fff' |
       '\uf900'..'\ufaff'
    ;

The simple test is: fsm Test

[kaby76]

• Make sure you select the "Lexer" tab and clear out the contents. You did not, which is why you get the error message "<missing 'fsm'>".
• Make sure you have a whitespace rule that shunts spaces to the off-channel. WS: [ \t\n] -> channel(HIDDEN);
• Make sure you use the +-operator in the definition of ID. ID: Letter+ ; not ID: Letter ;
• Make sure you use an EOF-terminated start rule in order to avoid the parser not reading all the input on failure. fsm: 'fsm' ID EOF;. If you do all three changes I listed before this fourth suggestion, and give fsm Test foobar as input, the parse will succeed, but not fail on foobar.

Your grammar should looke like this:

grammar Fsm;
fsm :   'fsm' ID ;
ID:   Letter+  ;
WS: [ \t\n] -> channel(HIDDEN);
fragment
Letter
    :  '\u0024'           /* $   */ |
       '\u0041'..'\u005a' /* A-Z */ |
       '\u005f'           /* _   */ |
       '\u0061'..'\u007a' /* a-z */ |
       '\u00c0'..'\u00d6' |
       '\u00d8'..'\u00f6' |
       '\u00f8'..'\u00ff' |
       '\u0100'..'\u1fff' |
       '\u3040'..'\u318f' |
       '\u3300'..'\u337f' |
       '\u3400'..'\u3d2d' |
       '\u4e00'..'\u9fff' |
       '\uf900'..'\ufaff'
    ;