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Add `pg.distinct`

Open aleclarson opened this issue 3 years ago • 0 comments

// SELECT DISTINCT ON(name) FROM "user"
db.select(t.user(user => pg.distinct(user.name)))

// SELECT COUNT(DISTINCT name) FROM "user"
db.select(t.user(user => pg.count(pg.distinct(user.name))))

aleclarson avatar Sep 05 '22 22:09 aleclarson