对char类型支持有缺陷，请确认

[yanchenyuvip]

char type=2;

LOG(INFO)<<"type="<<type; //output is false！ type=
LOG(INFO)<<"type="<<(u_char)type; //output is true! type=2

[SnorlaxGengar]

It use std::stringstream or std::wstringsteam to format, ref to this. you can test use this:

    std::stringstream ss;
    ss << static_cast<int>(type) << " vs " << type;
    std::cout << ss.str();

LOG(INFO)<<"type="<<type; //output is false！ type=

this is not output empty, because the ascii char 2 is control char.

[yanchenyuvip]

It use std::stringstream or std::wstringsteam to format, ref to this. you can test use this:

    std::stringstream ss;
    ss << static_cast<int>(type) << " vs " << type;
    std::cout << ss.str();

LOG(INFO)<<"type="<<type; //output is false！ type=

this is not output empty, because the ascii char 2 is control char.

According to you say，So “unsigned char” is error！

unsigned char type=65;
cout<<"type="<<type<<endl;//type=A
LOG(INFO)<<"type="<<type; //output is false！ type=65

[SnorlaxGengar]

It use std::stringstream or std::wstringsteam to format, ref to this. you can test use this:

    std::stringstream ss;
    ss << static_cast<int>(type) << " vs " << type;
    std::cout << ss.str();

LOG(INFO)<<"type="<<type; //output is false！ type=

this is not output empty, because the ascii char 2 is control char.

According to you say，So “unsigned char” is error！

unsigned char type=65;
cout<<"type="<<type<<endl;//type=A
LOG(INFO)<<"type="<<type; //output is false！ type=65

have you define macro ELPP_UNICODE? if you define it, std::wstringstream is used.

    unsigned char type = 65;
    std::wstringstream ss;
    ss << type;
    std::wcout << "type=" << ss.str() << std::endl; //type=65