Doesn't work with prototype functions

[ThaisRobba]

I cannot get the documentation to show for the prototypes of a function. Example:

/**
@class View
@constructor
*/
function View () {}

/**
@method render
*/
View.prototype.render = function (data) {}

Using QuickDocs on the second function returns the "No Quick Docs available for current cursor position", even if the cursor is ontop of View. This, however, works:

/**
@class View
@constructor
*/
function View () {}

/**
@method render
*/
View.render = function (data) {}

[Wikunia]

Thanks I will have a look later today.

[Wikunia]

Can you @OttoRobba send me the code where you want to get the QuickDocs? So in which way do you call the View.render function?

[ThaisRobba]

A more concrete example:

/**
 * @namespace ox
 */
var ox = {};
/**
 * Creates a sprite!
 * @class Sprite
 * @memberof ox
 * @param {String} src image source file
 * @example var player = new ox.Sprite("player.png");
 */
ox.Sprite = function (src) {
  this.x = 0;
  this.y = 0;
  this.alpha = 1;
  this.src = src;
  return this;
};
/** @lends ox.Sprite.prototype */

/**
 * Crops the image
 * @memberof ox.Sprite
 * @param {Number} x
 * @param {Number} y
 * @param {Number} w
 * @param {Number} h
 */
ox.Sprite.prototype.crop = function (x, y, w, h) {
  return this;
}

[Wikunia]

I mean sth. like:

/**
 * [[Description]]
 * @param {[[Type]]} abc [[Description]]
 */
Array.prototype.stuff = function(abc) {

}

var arr = ['abc','def'];
arr.stuff('abc');

is working cause the program gets that arr is an array so it can check Array.prototype function. But it's probably hard to determine the type of the variable for other types :/ On the other hand if someone has two prototypes one with Array and one with View where the function name is the same I don't want to show the first one I can get.

[ThaisRobba]

I can see how this is a difficult problem. Very likely I'm being naïve here but for anything that is not monkey patching, wouldn't just using the information from @memberof solve this? It is telling us who it belongs to, just treat it as a method of that member.

[Wikunia]

Well unfortunately it isn't that easy cause I can't run your code to get this information. So I have to rebuilt the memberof function just by reading the code. At the moment I don't parse your whole code. I'm just using regex to "understand" it and this is probably the problem :/ but I think it's hard to change everything and I never worked with parser before.