Turn off a particular bit in a number.

[Gouriiseth]

Detailed description

Let's have a number n and a value k, we need to turn off the k'th bit in n numbers. Note: count starts from the rightmost bit in accordance with k. eg -> k=1 means the rightmost bit.

Input: n = 15, k = 1 Output: 14

Input: n = 14, k = 1 Output: 14 The rightmost bit was already off, so no change.

Context

By solving this problem, we can implement it in real life. As to find system failures due to some unavoidable resistor shutdowns or connection flaws.

Possible implementation

We can use bitwise operators like AND(&&) NOT(~) or Left Shift Operator(<<). Using expression ~(1<<(k-1)), we get a number that has all bits set, except the k'th bit. If we do bitwise & of this expression with n, we get a number that has all the bits the same as n except the k'th bit which is 0.

//below is the cpp implementation

#include <bits/stdc++.h> using namespace std;

// Returns a number that has all bits same as n // except the k'th bit which is made 0

int turnOffK(int n, int k) { // k must be greater than 0 if (k <= 0) return n;

// Do & of n with a number with all set bits except
// the k'th bit
return (n & ~(1 << (k - 1)));

}

// Driver program to test above function int main() { int n = 15; int k = 4; cout << turnOffK(n, k); return 0; }

Additional information

No response

[Gouriiseth]

#2252 is the issue resolved by creating a bit manipulation question.

[BhavinSonagara]

can you assign this issue to me

[ishita126jain]

Can you assign this issue to me?

[himanshukrabc]

can you assign this to me?

[XxBeyonderxX]

can you assign this to me?

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