Rubi
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RuleBasedIntegration
Rubi for Mathematica
Once #15 is implemented and we have a `::usage` message for the integration-step condition function, this information should be included in the `Steps` display. I imagine for instance a tooltip...
I tried: Int[((x^2 - 2)*Exp[x])/((x - 1)*Sqrt[1 - x^2]), x] give me: Int[E^x/Sqrt[1 - x^2], x] + Int[E^x/((1 - x) Sqrt[1 - x^2]), x] + Int[(E^x x)/Sqrt[1 - x^2], x]...
If we work within real numbers (which I guess is the case for a lot of people), correct antiderivative of 1/x is Log[RealAbs[x]]. Can we get it somehow instead of...
Dear Rubi Team, I started a port of Rubi to Maxima, which is based on the idea of the late Albert Rich to automatically convert the rule base to a...
it says PacletInstall["https://rulebasedintegration.org/Rubi-4.16.1.0.paclet"] but the latest version is 4.17.3.0
I'm using Maxima's inherent rule methods with the suite of rules provided by RUBI for this particular Computer Algebra System . Once completed, might I upload the resultant files here...
Reported to me via email from Arthur Norman: The rule Int[AA1:(a_.+c_.*x_^2)^p_*(d_.+e_.*x_+f_.*x_^2)^q_,AA2:x_Symbol] := (2*c*x)*(a+c*x^2)^(p+1)*(d+e*x+f*x^2)^q/((-4*a*c)*(p+1)) - (1/((-4*a*c)*(p+1))) \[Star] Int[(a+c*x^2)^(p+1)*(d+e*x+f*x^2)^(q-1)* Simp[2*c*d*(2*p+3)+(2*c*e*(2*p+q+3))*x+2*c*f*(2*p+2*q+3)*x^2,x],x] /; FreeQ[{a,c,d,e,f},x] && NeQ[e^2-4*d*f] && 4 LtQ[p,-1] && GtQ[q,0] && Not[IGtQ[q,0]] calls...
I recently upgraded computer and reinstalled the latest Wolfram Engine 14.3. I installed the latest Rubi `PacletInstall["https://rulebasedintegration.org/Rubi-4.17.3.0.paclet"]` and ran into an issue. It is actually visible from the example given...
