Timothy Stiles

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Oh, there's a slog approximation on its page: https://en.wikipedia.org/wiki/Super-logarithm#Approximations Maybe I could try it sometime. https://en.wikipedia.org/wiki/Iterated_logarithm 'Iterated Logarithm" aka log* is almost the same too. As for sroot, we can...

slog implemented - and since it uses the same linear approximation as tetrate, they are truly inverses of each other!

This is still an open issue. Now that slog uses guess-and-check to get exact values, the precedent has been set to write an sroot that accepts arbitrary arguments. Of course,...

Yep! Specifically if a^^b == c, then sroot_b(c) == a

Works great. ``` new Decimal(10).tetrate(0.9).toString() '6.989961179534713' new Decimal(10).tetrate(0.5).toString() '2.4770056063449646' ```

Maybe we could find inspiration in big O notation and ordinal collapsing functions/fast growing hierarchies/slow hierarchies, which are basically the language for describing how fast functions grow. https://www.reddit.com/r/incremental_games/comments/2ztcfk/linear_polynomial_exponential_and_more_growth/ https://oeis.org/wiki/Growth_of_sequences https://en.wikipedia.org/wiki/Big_O_notation...

https://sites.google.com/site/pointlesslargenumberstuff/home/2/weakoperators is an interesting article that describes 'Weak' Hyperoperators. So called 'Strong' Tetration and Pentation evaluates right to left so as to get the most massive numbers, but the 'Weak'...

https://math.blogoverflow.com/tag/super-square-root/ Since I don't have a better place to put this, identities and growth rate for tetration. https://andydude.github.io/tetration/archives/tetration2/ident.html Some more.

random idea would be: you could slog both numbers, then do some math on the slogs, then base 10 tetrate them back into hueg numbers. but then aren't you just...