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SyntaxError: 'return' outside of function (3:4)

Open batongprodt opened this issue 6 months ago • 3 comments

SyntaxError: 'return' outside of function (3:4)

var base_url = window.location.host; if (base_url != "example.com") return; Why did the error occur?

batongprodt avatar Dec 26 '23 03:12 batongprodt