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Unable to use f-string in SqlAlchemy ORM

Open ruslaniv opened this issue 3 years ago • 1 comments

  • asyncpg version: 0.23.0
  • PostgreSQL version: 12
  • Python version: 3.9.4
  • Platform: OSX
  • Do you use pgbouncer?: No
  • Did you install asyncpg with pip?: pipenv
  • If you built asyncpg locally, which version of Cython did you use?: N/A
  • Can the issue be reproduced under both asyncio and uvloop?: N/A

I'm trying to build a SQL statement with LIKE expression and a pattern but I'm getting an error.

Here is what I had in the code originally:

statement = select(Customer).options(sqlalchemy.orm.joinedload(Customer.transactions)).where(Customer.l_name.ilike(name))

and this worked great.

But if I want to use this statement with a % pattern like this:

statement = f'select(Customer).options(sqlalchemy.orm.joinedload(Customer.transactions)).where(Customer.l_name.ilike("%{name}%"))'

I get this error:

sqlalchemy.exc.ProgrammingError: (sqlalchemy.dialects.postgresql.asyncpg.ProgrammingError) <class 'asyncpg.exceptions.PostgresSyntaxError'>: syntax error at or near "("
[SQL: select(Customer).options(sqlalchemy.orm.joinedload(Customer.transactions)).where(Customer.l_name.ilike("%%turing%%"))]

It does substitute the variable with a parameter but for some reason it adds an extra pair of percent signs and crashes. How can I solve this problem?

ruslaniv avatar Jul 14 '21 09:07 ruslaniv

There is a big difference between statement = select(...) and statement = "select(...)"

The first one is actually calling select and the second one is just a string. You should try something like that though I haven't tested it:

statement = select(Customer).options(sqlalchemy.orm.joinedload(Customer.transactions)).where(Customer.l_name.ilike(f'%{name}%'))

hrist0stoichev avatar Jul 28 '21 18:07 hrist0stoichev