Timofey Kazantsev

Well, I still think that a brief look at the code will be more useful. If the issue is connected to several project tabs — there can be conflicts in...

Well. I ask You again to put Your code inside \`\`\` symbols :) I feel no powers now to try to reproduce Your bug live. But I feel the problem...

OK, I've read the whole topic. And now I'm much more interesting in the way You run the script. If You run it from the outside — it looks stranger:...

I can say, what is the reason, but I cannot say right now, how to avoid it. I think, the reason is — the socket is being still opened for...

Last time I've done this this way: ```Python def make_copy( self, position: float, length: ty.Optional[float] = None, additional_source_offset: float = 0.0, ) -> 'ItemsHandler': """Make copy of items and place...

There is appropriate API call, which you can find in reascript documentation and use via ```PYTHON from reapy import reascript-api as RPR RPR.Function() ``` Also, you can load entire project...

@d-vyd , actually, all you need is the loading a track-template as project: ```Python import reapy as rpr pr = rpr.Project() template = rpr.open_project("/path/to/my.RTrackTemplate") ``` ### Considering a question about...

The real one problem is `@inside_reaper()` decorator. But, I think, I've already made its type work more or less well.

* At first, You should ensure reapy inside your python environment is exactly the same reapy Reaper using. * At the second, every change in core library has to be...

> @reapy.inside_reaper() Oh, forgot to mention. The class with this decorator inside `reapy.core` has to be imported up to the `core.__init__` P.S. Exactly, It has to be present in `reapy.core.__init__.__all__`