Deserialize sealed class with generic

[september669]

Is there are any way for deserialize classes like below? Tested in kotlin native

@Serializable
sealed class Foo<T> {
    abstract val value: T

    @Serializable
    data class BarInt(override val value: Int) : Foo<Int>()

    @Serializable
    data class BarFloat(override val value: Float) : Foo<Float>()
}

    @Test
    fun someFun() {
        val barInt: Foo<Int> = Foo.BarInt(42)
        val json = json().encodeToString(barInt)
        logError { "json: $json" }
        val decodedBarInt: Foo<*> = json().decodeFromString(json) <-- crashes here with message "Star projections in type arguments are not allowed, but had network.Foo<*> (Kotlin reflection is not available)"
        logError { "decodedBarInt: $decodedBarInt" }
    }

serialized json string:

json: {
    "type": "network.Foo.BarInt",
    "value": 42
}

[Dominaezzz]

Not yet but do you really need generics here? Especially since you end up doing Foo<*>.

What's wrong with this?

@Serializable
sealed class Foo {
    abstract val value: Any

    @Serializable
    data class BarInt(override val value: Int) : Foo()

    @Serializable
    data class BarFloat(override val value: Float) : Foo()
}

[september669]

Thanks for response! In my case i need something like this:

@Serializable
sealed class Foo<T> {
    abstract val x: T
    abstract val y: T

    @Serializable
    data class BarInt(
            override val x: Int,
            override val y: Int
    ) : Foo<Int>()

    @Serializable
    data class BarFloat(
            override val x: Float,
            override val y: Float
    ) : Foo<Float>()
}

I need to describe two values with same type for certain data class

[sandwwraith]

Workaround: use Json.decodeFromString(Foo.serializer(PolymorphicSerializer(Any::class)), json)