Jonney

This is my solution, no need to modify any code. Just write your own code. ```python import asyncio import uvloop import signal from pproxy import Server,Connection from pproxy.server import ProxyDirect...

You have to modify this line: https://github.com/qwj/python-proxy/blob/09d4752f17ed6787e1a073c93980eec019887ee3/pproxy/server.py#L82 to: ```python roption = choose(remote_ip) ``` And add this function: ```python def choose(remote_ip): if(remote_ip.startswith('192.168.')): return proxies_by_uri('socks5://192.168.0.1:8080') else: return proxies_by_uri('socks5://192.168.0.2:8080') ```

I think you don't have to modify the code. You just need to write your own code. ```python from pproxy import server,proto ARGS='-l socks5://127.0.0.1:8080#user:pass -r socks5://192.168.0.1:8080 -v' IP_WHITELIST=( '127.0.0.2', )...

Perhaps a block time of 4-6 seconds can solve this problem. [base-org/node#127(comment)](https://github.com/base-org/node/issues/127#issuecomment-1945516367) A 2-second block time will cause 3 issues: 1. Longer recovery time after node restart. 2. Longer recovery...

I have the same question: How to get the request in middleware after_request?

It's possible. Read the documents.

The coordinates obtained using subscribeCrosshairMove() are those of the mouse, not the crosshair. The only current solution is to use the development version instead of the production version. ``` const...