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A textbook on informal homotopy type theory

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Here's the proof for easy reference ![image](https://user-images.githubusercontent.com/17756312/177013817-7720daf2-b7f1-41ed-b6be-8d47f28881f5.png) (In what follows, I've renamed the $f $ in the proof to $\varphi $) For two fibers $(f , eqf) ,(g , eqg)...

First I will provide a snippet of the text for easy reference. ![image](https://user-images.githubusercontent.com/71675731/172908598-71cae815-7e6c-4eee-a7d2-a7711e1e9cc0.png) The first thing I wish to address is the use of 'naturality' in the first line of...

In basics.tex, line 1372 (proof of 2.6.4 in the book), the proof concludes with ``` Thus, it remains to show $x = (\proj1 x, \proj2x)$. But this is the propositional...

On the Unimath agda library discord, Martin Escardo wrote: > When we discuss syntax, we do define the terms of a type inductively together with the types themselves, and together...

In the 'first proof' of this lemma the following is stated > ![image](https://user-images.githubusercontent.com/71675731/168695241-bc30a6d5-f836-48b7-8c78-c5c8a6131e20.png) Here it is said, "We will instead define a function with the equivalent type...". What exactly is...

11.3.40 says that if we have `f : Q -> Q -> Q` non-expanding on both components then we can extend it to `f' : R -> R -> R`...

math bug
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In Section 1.12.2 a proof of the equivalence of path induction and based path induction is provided. I am confused about two things in the latter direction (i.e. path induction...

In option 4 of the ways to construct the single type Ω in defining Dedekind cuts, it says: > On the other end of the spectrum one might ask for...

Following the events of #1101, I am opening an issue to discuss the adoption of a code of conduct. Please note that we already are bound by the [GitHub Community...