Hadrian Tang

Results 569 comments of Hadrian Tang

limit((x^(1/2)+x^(-1/2))/(x^(1/2)-x^(-1/2)),x,Infinity) => (-limit(sqrt(x),x,Infinity)^(-1)+limit(sqrt(x),x,Infinity))^(-1)*(limit(sqrt(x),x,Infinity)+limit(sqrt(x),x,Infinity)^(-1)) unable to give 1 according to https://en.wikipedia.org/wiki/L%27Hôpital%27s_rule#Complications

limit((x+sin(x)cos(x))/(x+sin(x)cos(x))/e^(sin(x)), x, Infinity) => 119696244/325368125 but it should not be solvable according to https://en.wikipedia.org/wiki/L%27Hôpital%27s_rule#Counterexamples_when_the_derivative_of_the_denominator_is_zero

Ref: https://en.wikipedia.org/wiki/Seven-dimensional_cross_product 1. Set an setting for the basis vector (product of [1, 0, 0, 0, 0, 0, 0] and [0, 1, 0, 0, 0, 0, 0, 0] Something like...

Related parameters in my above incomplete form should be used with setFunction: ```js nerdamer.setFunction("func", ["x", "y=40-x"], "x+log(y)"); ```

>Should line also create parabolas etc? Just thought of an ambiguity: https://www.wolframalpha.com/input/?i=parabola+through+(1,2),(2,1),(3,3)+and+hyperbola+through+(1,2),(2,1),(3,3) Maybe separate functions for parabolas and hyperbolas.

>the difficulty of implementation using the current parser What about adding this during the rewrite of the parser in the upcoming 0.8.0?

A couple of questions to discuss: - What representation would be used to represent the geometric shapes? 1. Equations Pro: Integration with existing features, ease of understanding Con: More difficult...

>Hopefully when I do get the time to continue work on the library, you'll be available again. Thanks again. Definitely.

(Inserted into #202)

Ideally it would also do the rationalization, and here is a bunch of tests (not sending as PR as the syntax has not been confirmed): Input|My answer -|- 6/sqrt(3)|2sqrt(3) 1/(sqrt(2)-1)|sqrt(2)+1...