GetStream
Call participant view still on call after leaving
When someone leaves a call their block is still showing for others to see but is frozen. It should remove that person from the call altogether.
I am using the StreamCallContainer like so:
StreamCallContainer(
call: widget.call,
callConnectOptions: widget.options,
callContentBuilder: (context, call, callState) {
return StreamCallContent(
call: call,
callState: callState,
callAppBarBuilder: (context, call, callState) {
return AppBar();
},
callControlsBuilder: (context, call, callState) {
final localParticipant = callState.localParticipant!;
return StreamCallControls(
options: [
ToggleMicrophoneOption(
call: call,
localParticipant: localParticipant,
),
ToggleCameraOption(
call: call,
localParticipant: localParticipant,
),
FlipCameraOption(
call: call,
localParticipant: localParticipant,
),
LeaveCallOption(
call: call,
onLeaveCallTap: () => onleaveRoom(call),
),
],
);
},
);
},
)
Flutter (Channel stable, 3.22.2, on macOS 14.5 23F79 darwin-arm64, locale en-US)
Hey @rlee1990, this should likely have been resolved by recent versions.
How long does a participant linger in the call after quitting in your experience?
@deven98 so lets use this example. If user A starts the call and user B and user C join the call. If user B leaves the call user A and C still see the square and the last image of user B on their screens. I also have an issue with not being able to tell if someone is just a viewer of a live stream or if they are a host/co-host.
@deven98 this is the function:
hideBottomBar.value = false;
// if (widget.isHost) {
// timer2?.cancel();
// await widget.call.end();
// } else {
timer2?.cancel();
call.leave();
// }
AutoRouter.of(context).maybePop();
}
Here is where it is called:
StreamCallContainer(
call: widget.call,
callConnectOptions: widget.options,
callContentBuilder: (context, call, callState) {
return StreamCallContent(
call: call,
callState: callState,
callAppBarBuilder: (context, call, callState) {
return AppBar();
},
callControlsBuilder: (context, call, callState) {
final localParticipant = callState.localParticipant!;
return StreamCallControls(
options: [
ToggleMicrophoneOption(
call: call,
localParticipant: localParticipant,
),
ToggleCameraOption(
call: call,
localParticipant: localParticipant,
),
FlipCameraOption(
call: call,
localParticipant: localParticipant,
),
LeaveCallOption(
call: call,
onLeaveCallTap: () => onleaveRoom(call),
),
],
);
},
);
},
)
@deven98 I did some testing and saw that the person drops from the view after about a minute. Is there a way to get that down? Also, what is the best way for a live stream with a co-host to be shown while not showing a feed for a guest?
Hi @rlee1990 and @ascendooleg, could you check the logs for any errors? This shouldn't be happening, so I suspect that for some reason, the leave call request is failing. Please ensure you have log priority set to verbose before checking. Thank you.
StreamVideo(
options: const StreamVideoOptions(
logPriority: Priority.verbose,
),
);
(W/SV:RtcManager): [unpublishTrack] removeTrack failed: Unable to RTCPeerConnection::removeTrack: Error: sender not found!
⚠️ (W/SV:SdpEditor): [edit] rejected (mismatched platform): ios (W/SV:SdpEditor): [edit] rejected (mismatched sdpType): remoteOffer
(V/SV:SfuClient): [updateSubscriptions] response: error: { flutter: code: ERROR_CODE_REQUEST_VALIDATION_FAILED flutter: message: video and screenshare subscriptions must have non-zero dimensions flutter: } flutter: flutter: 2024-08-08 18:18:14.596365 🔍 (V/SV:CallSession-1): [updateSubscriptions] result: Result.Failure{error: VideoError{message: ERROR_CODE_REQUEST_VALIDATION_FAILED - video and screenshare subscriptions must have non-zero dimensions, stackTrace: null}}
(V/SV:CallSession-1): [_onSubsciberDisconnectedOrFailed] result: Result.Success{data: error: { flutter: code: ERROR_CODE_PARTICIPANT_NOT_FOUND flutter: message: participant not found: call_cid:"default:18284f12-4f26-462b-97ef-13c2eee52cbf", user_id: "607112940", session_id: "79f2e5b1-a0ef-4a93-b4e3-58de5701c3a1" flutter: }