JsonPath-PHP
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Remove without field
I did a bit of experimentation with a PR but wasn't quite able to get it to work, so I thought I'd take this to an issue to look for some ideas on how to implement :)
Given the sample document, I'm interested in being able to use remove()
without providing a field, e.g. removing all matching paths.
Essentially supporting something like this:
$jsonObject = new JsonObject($json);
$jsonObject->remove("$..book[?(@.category == 'fiction')]");
$results = $jsonObject->toValue();
// $results with all fiction books removed.
I tried a simple unset($element);
in the remove
code but PHP's unset only unsets the reference, not the original value, so it doesn't quite work.
Hi there! Sounds like a good addition.
Have you tried passing an optional parameter to getReal()
stating the action, ie.remove
, and have the remove logic happen when traversing the internal array? Instead of appending the match to $selection
you could unset it from its parent.
Hi ! Here some workarround
$exploded = explode(".", $fieldName);
$field = array_pop($exploded);
$imploded = implode(".", $exploded);
$jsonPath = "$";
if (!empty($imploded)) {
$jsonPath .= ".".$imploded;
}
$jsonPathObject->remove($jsonPath, $field);
It's works on simple cases like $.store.bicycle.price