@code_ir %8=(%7)(%6) what does this mean and what is the function for argnames! and updates!?

Open agdkyang opened this issue 5 years ago • 1 comments

@code_ir %8=(%7)(%6) what does this mean (means multiply or others)and what is the function for argnames! and updates!? Could the writer give us more examples for those API?

Jun 16 '20 08:06 agdkyang

I'm not sure I fully understand the question, you might need to give a bit more detail. In general that kind of syntax means that %7 is a function, which you're calling with %6 as an argument.

Jun 16 '20 16:06 MikeInnes