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Updating a value via the Watch View is not Reflected in the Memory View

Open mistymntncop opened this issue 1 year ago • 0 comments

When you manually update a value in the Watch View the updated value is not updated in the Memory View.

Steps to Reproduce:

  1. Compile this C code:
#include <stdio.h>
#include <stdint.h>

int main(void) {
    uint32_t values[] = {
        1,2,3,4,5
    };
    int set_a_break_here = 3;
    return 0;
}
  1. Set a breakpoint on "set_a_break_here" line
  2. Open Memory View and Go To Memory "&values"
  3. View "values" in Watch View and modify values[0] to be 0x1337

The updated value will not be shown in the Memory View. The value of values[0] is still shown as "1" in the Memory View.

mistymntncop avatar Jan 21 '24 02:01 mistymntncop